-1/3(2k-7/3)=1/6(4k-2)

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Solution for -1/3(2k-7/3)=1/6(4k-2) equation: 


k in (-oo:+oo)

(-1/3)*(2*k-(7/3)) = (1/6)*(4*k-2) // - (1/6)*(4*k-2)

(-1/3)*(2*k-(7/3))-((1/6)*(4*k-2)) = 0

(-1/3)*(2*k-7/3)+(-1/6)*(4*k-2) = 0

-1/3*(2*k-7/3)-1/6*(4*k-2) = 0

-1/3*(2*k-7/3)-1/6*(4*k-2) = 0

10/9-4/3*k = 0

10/9-4/3*k = 0

10/9-4/3*k = 0 // - 10/9

-4/3*k = -10/9 // : -4/3

k = -10/9/(-4/3)

k = 5/6

k = 5/6

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