-1/3(3b+12)=-6

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Solution for -1/3(3b+12)=-6 equation: 



-1/3(3b+12)=-6

We move all terms to the left:

-1/3(3b+12)-(-6)=0



Domain of the equation: 3(3b+12)!=0

b∈R



We add all the numbers together, and all the variables

-1/3(3b+12)+6=0

We multiply all the terms by the denominator


6*3(3b+12)-1=0

Wy multiply elements

18b(3-1=0

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