-1/3(3q+9)=1/4(8q)

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Solution for -1/3(3q+9)=1/4(8q) equation: 



-1/3(3q+9)=1/4(8q)

We move all terms to the left:

-1/3(3q+9)-(1/4(8q))=0



Domain of the equation: 3(3q+9)!=0

q∈R





Domain of the equation: 48q)!=0

q!=0/1

q!=0

q∈R



We add all the numbers together, and all the variables

-1/3(3q+9)-(+1/48q)=0

We get rid of parentheses

-1/3(3q+9)-1/48q=0

We calculate fractions


(-48q)/(432q^2+1296q)+(-3q3/(432q^2+1296q)=0



We calculate terms in parentheses: +(-3q3/(432q^2+1296q), so:

-3q3/(432q^2+1296q

We multiply all the terms by the denominator


-3q3

We add all the numbers together, and all the variables

-3q^3

We do not support eqpression: q^3

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