-1/3(3x-12)=1/6(24-6x)

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Solution for -1/3(3x-12)=1/6(24-6x) equation:



-1/3(3x-12)=1/6(24-6x)
We move all terms to the left:
-1/3(3x-12)-(1/6(24-6x))=0
Domain of the equation: 3(3x-12)!=0
x∈R
Domain of the equation: 6(24-6x))!=0
x∈R
We add all the numbers together, and all the variables
-1/3(3x-12)-(1/6(-6x+24))=0
We calculate fractions
(-6x(-)/(3(3x-12)*6(-6x+24)))+(-3x3/(3(3x-12)*6(-6x+24)))=0
We calculate terms in parentheses: +(-6x(-)/(3(3x-12)*6(-6x+24))), so:
-6x(-)/(3(3x-12)*6(-6x+24))
We add all the numbers together, and all the variables
-6x0/(3(3x-12)*6(-6x+24))
We multiply all the terms by the denominator
-6x0
We add all the numbers together, and all the variables
-6x
Back to the equation:
+(-6x)
We calculate terms in parentheses: +(-3x3/(3(3x-12)*6(-6x+24))), so:
-3x3/(3(3x-12)*6(-6x+24))
We multiply all the terms by the denominator
-3x3
We add all the numbers together, and all the variables
-3x^3
We do not support expression: x^3

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