-1/3(6x-5)=1/2(10x-4)

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Solution for -1/3(6x-5)=1/2(10x-4) equation: 



-1/3(6x-5)=1/2(10x-4)

We move all terms to the left:

-1/3(6x-5)-(1/2(10x-4))=0



Domain of the equation: 3(6x-5)!=0

x∈R





Domain of the equation: 2(10x-4))!=0

x∈R



We calculate fractions


(-2x1/(3(6x-5)*2(10x-4)))+(-3x6/(3(6x-5)*2(10x-4)))=0



We calculate terms in parentheses: +(-2x1/(3(6x-5)*2(10x-4))), so:

-2x1/(3(6x-5)*2(10x-4))

We multiply all the terms by the denominator


-2x1

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)





We calculate terms in parentheses: +(-3x6/(3(6x-5)*2(10x-4))), so:

-3x6/(3(6x-5)*2(10x-4))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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