-1/3(9x-27)=2/3(6x-18)

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Solution for -1/3(9x-27)=2/3(6x-18) equation: 



-1/3(9x-27)=2/3(6x-18)

We move all terms to the left:

-1/3(9x-27)-(2/3(6x-18))=0



Domain of the equation: 3(9x-27)!=0

x∈R





Domain of the equation: 3(6x-18))!=0

x∈R



We calculate fractions


(-3x6/(3(9x-27)*3(6x-18)))+(-6x9/(3(9x-27)*3(6x-18)))=0



We calculate terms in parentheses: +(-3x6/(3(9x-27)*3(6x-18))), so:

-3x6/(3(9x-27)*3(6x-18))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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