-1/3b-2/5=2

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Solution for -1/3b-2/5=2 equation: 


b in (-oo:+oo)

(-1/3)*b-(2/5) = 2 // - 2

(-1/3)*b-(2/5)-2 = 0

(-1/3)*b-2/5-2 = 0

-1/3*b-12/5 = 0 // + 12/5

-1/3*b = 12/5 // : -1/3

b = 12/5/(-1/3)

b = -36/5

b = -36/5

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