-1/3c+2/5c+12=1/2c+3

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Solution for -1/3c+2/5c+12=1/2c+3 equation: 



-1/3c+2/5c+12=1/2c+3

We move all terms to the left:

-1/3c+2/5c+12-(1/2c+3)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R





Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R





Domain of the equation: 2c+3)!=0

c∈R



We get rid of parentheses

-1/3c+2/5c-1/2c-3+12=0

We calculate fractions

We do not support ecpression: c^3

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