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-1/3v-17/18=1/4v+1
We move all terms to the left:
-1/3v-17/18-(1/4v+1)=0
Domain of the equation: 3v!=0
v!=0/3
v!=0
v∈R
Domain of the equation: 4v+1)!=0We get rid of parentheses
v∈R
-1/3v-1/4v-1-17/18=0
We calculate fractions
(-816v^2)/216v^2+(-72v)/216v^2+(-54v)/216v^2-1=0
We multiply all the terms by the denominator
(-816v^2)+(-72v)+(-54v)-1*216v^2=0
Wy multiply elements
(-816v^2)-216v^2+(-72v)+(-54v)=0
We get rid of parentheses
-816v^2-216v^2-72v-54v=0
We add all the numbers together, and all the variables
-1032v^2-126v=0
a = -1032; b = -126; c = 0;
Δ = b2-4ac
Δ = -1262-4·(-1032)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-126}{2*-1032}=\frac{0}{-2064} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+126}{2*-1032}=\frac{252}{-2064} =-21/172 $
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