-1/3x+(-2/3x)=-x

Solution for -1/3x+(-2/3x)=-x equation:

-1/3x+(-2/3x)=-x

We move all terms to the left:

-1/3x+(-2/3x)-(-x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-1/3x+(-2/3x)-(-1x)=0

We get rid of parentheses

-1/3x-2/3x+1x=0

We multiply all the terms by the denominator


1x*3x-1-2=0

We add all the numbers together, and all the variables

1x*3x-3=0

Wy multiply elements

3x^2-3=0

a = 3; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·3·(-3)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*3}=\frac{6}{6}
=1
$