-1/3x+12=-x+8

Solution for -1/3x+12=-x+8 equation:

-1/3x+12=-x+8

We move all terms to the left:

-1/3x+12-(-x+8)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-1/3x-(-1x+8)+12=0

We get rid of parentheses

-1/3x+1x-8+12=0

We multiply all the terms by the denominator


1x*3x-8*3x+12*3x-1=0

Wy multiply elements

3x^2-24x+36x-1=0

We add all the numbers together, and all the variables

3x^2+12x-1=0

a = 3; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·3·(-1)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{39}}{2*3}=\frac{-12-2\sqrt{39}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{39}}{2*3}=\frac{-12+2\sqrt{39}}{6}
$