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-1/3x+5=7+5/6x
We move all terms to the left:
-1/3x+5-(7+5/6x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/3x-(5/6x+7)+5=0
We get rid of parentheses
-1/3x-5/6x-7+5=0
We calculate fractions
(-6x)/18x^2+(-15x)/18x^2-7+5=0
We add all the numbers together, and all the variables
(-6x)/18x^2+(-15x)/18x^2-2=0
We multiply all the terms by the denominator
(-6x)+(-15x)-2*18x^2=0
Wy multiply elements
-36x^2+(-6x)+(-15x)=0
We get rid of parentheses
-36x^2-6x-15x=0
We add all the numbers together, and all the variables
-36x^2-21x=0
a = -36; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·(-36)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*-36}=\frac{0}{-72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*-36}=\frac{42}{-72} =-7/12 $
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