-1/3x+7=3/5x-7

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Solution for -1/3x+7=3/5x-7 equation:



-1/3x+7=3/5x-7
We move all terms to the left:
-1/3x+7-(3/5x-7)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x-7)!=0
x∈R
We get rid of parentheses
-1/3x-3/5x+7+7=0
We calculate fractions
(-5x)/15x^2+(-9x)/15x^2+7+7=0
We add all the numbers together, and all the variables
(-5x)/15x^2+(-9x)/15x^2+14=0
We multiply all the terms by the denominator
(-5x)+(-9x)+14*15x^2=0
Wy multiply elements
210x^2+(-5x)+(-9x)=0
We get rid of parentheses
210x^2-5x-9x=0
We add all the numbers together, and all the variables
210x^2-14x=0
a = 210; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·210·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*210}=\frac{0}{420} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*210}=\frac{28}{420} =1/15 $

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