-1/4(40-8x)=19x+2-5x

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Solution for -1/4(40-8x)=19x+2-5x equation: 



-1/4(40-8x)=19x+2-5x

We move all terms to the left:

-1/4(40-8x)-(19x+2-5x)=0



Domain of the equation: 4(40-8x)!=0

x∈R



We add all the numbers together, and all the variables

-1/4(-8x+40)-(14x+2)=0

We get rid of parentheses

-1/4(-8x+40)-14x-2=0

We multiply all the terms by the denominator


-14x*4(-8x+40)-2*4(-8x+40)-1=0

Wy multiply elements

-56x^2(--8x(--1=0

We use the square of the difference formula

-56x^2(+8x(+1=0

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