-1/4p=-8p=

Solution for -1/4p=-8p= equation:

-1/4p=-8p=

We move all terms to the left:

-1/4p-(-8p)=0


Domain of the equation: 4p!=0

p!=0/4

p!=0

p∈R


We get rid of parentheses

-1/4p+8p=0

We multiply all the terms by the denominator


8p*4p-1=0

Wy multiply elements

32p^2-1=0

a = 32; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·32·(-1)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{2}}{2*32}=\frac{0-8\sqrt{2}}{64}
=-\frac{8\sqrt{2}}{64}
=-\frac{\sqrt{2}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{2}}{2*32}=\frac{0+8\sqrt{2}}{64}
=\frac{8\sqrt{2}}{64}
=\frac{\sqrt{2}}{8}
$