-1/4x+16=-x+4

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Solution for -1/4x+16=-x+4 equation:



-1/4x+16=-x+4
We move all terms to the left:
-1/4x+16-(-x+4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We add all the numbers together, and all the variables
-1/4x-(-1x+4)+16=0
We get rid of parentheses
-1/4x+1x-4+16=0
We multiply all the terms by the denominator
1x*4x-4*4x+16*4x-1=0
Wy multiply elements
4x^2-16x+64x-1=0
We add all the numbers together, and all the variables
4x^2+48x-1=0
a = 4; b = 48; c = -1;
Δ = b2-4ac
Δ = 482-4·4·(-1)
Δ = 2320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2320}=\sqrt{16*145}=\sqrt{16}*\sqrt{145}=4\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-4\sqrt{145}}{2*4}=\frac{-48-4\sqrt{145}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+4\sqrt{145}}{2*4}=\frac{-48+4\sqrt{145}}{8} $

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