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-1/4x+6=1/2x+3
We move all terms to the left:
-1/4x+6-(1/2x+3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
-1/4x-1/2x-3+6=0
We calculate fractions
(-2x)/8x^2+(-4x)/8x^2-3+6=0
We add all the numbers together, and all the variables
(-2x)/8x^2+(-4x)/8x^2+3=0
We multiply all the terms by the denominator
(-2x)+(-4x)+3*8x^2=0
Wy multiply elements
24x^2+(-2x)+(-4x)=0
We get rid of parentheses
24x^2-2x-4x=0
We add all the numbers together, and all the variables
24x^2-6x=0
a = 24; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·24·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*24}=\frac{12}{48} =1/4 $
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