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-1/4x-(1/5x+4)+12=17x-6(3x+5/6)
We move all terms to the left:
-1/4x-(1/5x+4)+12-(17x-6(3x+5/6))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x+4)!=0We add all the numbers together, and all the variables
x∈R
-1/4x-(1/5x+4)-(17x-6(+3x+5/6))+12=0
We get rid of parentheses
-1/4x-1/5x-(17x-6(+3x+5/6))-4+12=0
We calculate fractions
We do not support expression: x^3
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