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-1/4x-5=10+1x
We move all terms to the left:
-1/4x-5-(10+1x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-1/4x-(x+10)-5=0
We get rid of parentheses
-1/4x-x-10-5=0
We multiply all the terms by the denominator
-x*4x-10*4x-5*4x-1=0
Wy multiply elements
-4x^2-40x-20x-1=0
We add all the numbers together, and all the variables
-4x^2-60x-1=0
a = -4; b = -60; c = -1;
Δ = b2-4ac
Δ = -602-4·(-4)·(-1)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-16\sqrt{14}}{2*-4}=\frac{60-16\sqrt{14}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+16\sqrt{14}}{2*-4}=\frac{60+16\sqrt{14}}{-8} $
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