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-1/4x=3x-12
We move all terms to the left:
-1/4x-(3x-12)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
-1/4x-3x+12=0
We multiply all the terms by the denominator
-3x*4x+12*4x-1=0
Wy multiply elements
-12x^2+48x-1=0
a = -12; b = 48; c = -1;
Δ = b2-4ac
Δ = 482-4·(-12)·(-1)
Δ = 2256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2256}=\sqrt{16*141}=\sqrt{16}*\sqrt{141}=4\sqrt{141}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-4\sqrt{141}}{2*-12}=\frac{-48-4\sqrt{141}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+4\sqrt{141}}{2*-12}=\frac{-48+4\sqrt{141}}{-24} $
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