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-1/4y-3=6y-26
We move all terms to the left:
-1/4y-3-(6y-26)=0
Domain of the equation: 4y!=0We get rid of parentheses
y!=0/4
y!=0
y∈R
-1/4y-6y+26-3=0
We multiply all the terms by the denominator
-6y*4y+26*4y-3*4y-1=0
Wy multiply elements
-24y^2+104y-12y-1=0
We add all the numbers together, and all the variables
-24y^2+92y-1=0
a = -24; b = 92; c = -1;
Δ = b2-4ac
Δ = 922-4·(-24)·(-1)
Δ = 8368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8368}=\sqrt{16*523}=\sqrt{16}*\sqrt{523}=4\sqrt{523}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-4\sqrt{523}}{2*-24}=\frac{-92-4\sqrt{523}}{-48} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+4\sqrt{523}}{2*-24}=\frac{-92+4\sqrt{523}}{-48} $
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