-1/5(10-20u)-u=1/3(6u-12)

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Solution for -1/5(10-20u)-u=1/3(6u-12) equation: 



-1/5(10-20u)-u=1/3(6u-12)

We move all terms to the left:

-1/5(10-20u)-u-(1/3(6u-12))=0



Domain of the equation: 5(10-20u)!=0

u∈R





Domain of the equation: 3(6u-12))!=0

u∈R



We add all the numbers together, and all the variables

-1/5(-20u+10)-u-(1/3(6u-12))=0

We add all the numbers together, and all the variables

-1u-1/5(-20u+10)-(1/3(6u-12))=0

We calculate fractions


-1u+(-3u6/(5(-20u+10)*3(6u-12)))+(-5u0/(5(-20u+10)*3(6u-12)))=0



We calculate terms in parentheses: +(-3u6/(5(-20u+10)*3(6u-12))), so:

-3u6/(5(-20u+10)*3(6u-12))

We multiply all the terms by the denominator


-3u6

We add all the numbers together, and all the variables

-3u^6

We do not support eupression: u^6

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