-1/5(5y-4)-3/10(-4y-5)=19/10

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Solution for -1/5(5y-4)-3/10(-4y-5)=19/10 equation: 



-1/5(5y-4)-3/10(-4y-5)=19/10

We move all terms to the left:

-1/5(5y-4)-3/10(-4y-5)-(19/10)=0



Domain of the equation: 5(5y-4)!=0

y∈R





Domain of the equation: 10(-4y-5)!=0

y∈R



We add all the numbers together, and all the variables

-1/5(5y-4)-3/10(-4y-5)-(+19/10)=0

We get rid of parentheses

-1/5(5y-4)-3/10(-4y-5)-19/10=0

We calculate fractions


(-100y(-)/(5(5y-4)*10(-4y-5)*10)+(-15y5/(5(5y-4)*10(-4y-5)*10)+(-95y5/(5(5y-4)*10(-4y-5)*10)=0



We calculate terms in parentheses: +(-100y(-)/(5(5y-4)*10(-4y-5)*10)+(-15y5/(5(5y-4)*10(-4y-5)*10)+(-95y5/(5(5y-4)*10(-4y-5)*10), so:

-100y(-)/(5(5y-4)*10(-4y-5)*10)+(-15y5/(5(5y-4)*10(-4y-5)*10)+(-95y5/(5(5y-4)*10(-4y-5)*10

We can not solve this equation

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