-1/5(b-4)=2

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Solution for -1/5(b-4)=2 equation: 



-1/5(b-4)=2

We move all terms to the left:

-1/5(b-4)-(2)=0



Domain of the equation: 5(b-4)!=0

b∈R



We multiply all the terms by the denominator


-2*5(b-4)-1=0

Wy multiply elements

-10b(b-1=0

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