-1/5c+2+c=1/5(10c-20)

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Solution for -1/5c+2+c=1/5(10c-20) equation: 



-1/5c+2+c=1/5(10c-20)

We move all terms to the left:

-1/5c+2+c-(1/5(10c-20))=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R





Domain of the equation: 5(10c-20))!=0

c∈R



We add all the numbers together, and all the variables

c-1/5c-(1/5(10c-20))+2=0

We calculate fractions


c+(-5c1/(25c^21+(-(1*5c)/(25c^21+2=0

We do not support ecpression: c^21

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