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-1/5r=2r+1
We move all terms to the left:
-1/5r-(2r+1)=0
Domain of the equation: 5r!=0We get rid of parentheses
r!=0/5
r!=0
r∈R
-1/5r-2r-1=0
We multiply all the terms by the denominator
-2r*5r-1*5r-1=0
Wy multiply elements
-10r^2-5r-1=0
a = -10; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·(-10)·(-1)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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