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-1/5x+30=-2x+3
We move all terms to the left:
-1/5x+30-(-2x+3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-1/5x+2x-3+30=0
We multiply all the terms by the denominator
2x*5x-3*5x+30*5x-1=0
Wy multiply elements
10x^2-15x+150x-1=0
We add all the numbers together, and all the variables
10x^2+135x-1=0
a = 10; b = 135; c = -1;
Δ = b2-4ac
Δ = 1352-4·10·(-1)
Δ = 18265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135)-\sqrt{18265}}{2*10}=\frac{-135-\sqrt{18265}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135)+\sqrt{18265}}{2*10}=\frac{-135+\sqrt{18265}}{20} $
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