-1/6(x+12)+1/3(x+3)=x+18

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Solution for -1/6(x+12)+1/3(x+3)=x+18 equation: 



-1/6(x+12)+1/3(x+3)=x+18

We move all terms to the left:

-1/6(x+12)+1/3(x+3)-(x+18)=0



Domain of the equation: 6(x+12)!=0

x∈R





Domain of the equation: 3(x+3)!=0

x∈R



We get rid of parentheses

-1/6(x+12)+1/3(x+3)-x-18=0

We calculate fractions


-x+(-3xx/(6(x+12)*3(x+3))+(6xx/(6(x+12)*3(x+3))-18=0

We can not solve this equation

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