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-1/6(x-12)+1/2(x+2)=x-12
We move all terms to the left:
-1/6(x-12)+1/2(x+2)-(x-12)=0
Domain of the equation: 6(x-12)!=0
x∈R
Domain of the equation: 2(x+2)!=0We get rid of parentheses
x∈R
-1/6(x-12)+1/2(x+2)-x+12=0
We calculate fractions
-x+(-2xx/(6(x-12)*2(x+2))+(6xx/(6(x-12)*2(x+2))+12=0
We can not solve this equation
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