-1/6(x-12)=1/2(x+2)=x-5

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Solution for -1/6(x-12)=1/2(x+2)=x-5 equation: 



-1/6(x-12)=1/2(x+2)=x-5

We move all terms to the left:

-1/6(x-12)-(1/2(x+2))=0



Domain of the equation: 6(x-12)!=0

x∈R





Domain of the equation: 2(x+2))!=0

x∈R



We calculate fractions


(-2xx/(6(x-12)*2(x+2)))+(-6xx/(6(x-12)*2(x+2)))=0



We calculate terms in parentheses: +(-2xx/(6(x-12)*2(x+2))), so:

-2xx/(6(x-12)*2(x+2))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)





We calculate terms in parentheses: +(-6xx/(6(x-12)*2(x+2))), so:

-6xx/(6(x-12)*2(x+2))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

-2xx-6xx=0

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