-1/6(x-18)1/2(x+2)=x+16

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Solution for -1/6(x-18)1/2(x+2)=x+16 equation: 


x in (-oo:+oo)

(((-1/6)*(x-18)^1)/2)*(x+2) = x+16 // - x+16

(((-1/6)*(x-18)^1)/2)*(x+2)-x-16 = 0

(((-1/6)*(x-18))/2)*(x+2)-x-16 = 0

(-1/6*(x-18)*(x+2))/2-x-16 = 0

(-1/6*(x-18)*(x+2))/2+(2*(-x))/2+(-16*2)/2 = 0

2*(-x)-1/6*(x-18)*(x+2)-16*2 = 0

2/3*x-1/6*x^2-32+6 = 0

2/3*x-1/6*x^2-26 = 0

2/3*x-1/6*x^2-26 = 0

2/3*x-1/6*x^2-26 = 0

DELTA = (2/3)^2-(-26*(-1/6)*4)

DELTA = -152/9

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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