-1/6(x-18)1/3(x+3)=x+9

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Solution for -1/6(x-18)1/3(x+3)=x+9 equation:


x in (-oo:+oo)

(((-1/6)*(x-18)^1)/3)*(x+3) = x+9 // - x+9

(((-1/6)*(x-18)^1)/3)*(x+3)-x-9 = 0

(((-1/6)*(x-18))/3)*(x+3)-x-9 = 0

(-1/6*(x-18)*(x+3))/3-x-9 = 0

(-1/6*(x-18)*(x+3))/3+(3*(-x))/3+(-9*3)/3 = 0

3*(-x)-1/6*(x-18)*(x+3)-9*3 = 0

9-1/6*x^2-1/2*x-27 = 0

-1/6*x^2-1/2*x-18 = 0

-1/6*x^2-1/2*x-18 = 0

-1*(1/6*x^2+1/2*x+18) = 0

1/6*x^2+1/2*x+18 = 0

DELTA = (1/2)^2-(1/6*4*18)

DELTA = -47/4

DELTA < 0

-1 = 0

-1/3 = 0

-1/3 = 0 // * 3

-1 = 0

x belongs to the empty set

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