-1/6(x-2)+1/3(x+3)=x-7

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Solution for -1/6(x-2)+1/3(x+3)=x-7 equation:



-1/6(x-2)+1/3(x+3)=x-7
We move all terms to the left:
-1/6(x-2)+1/3(x+3)-(x-7)=0
Domain of the equation: 6(x-2)!=0
x∈R
Domain of the equation: 3(x+3)!=0
x∈R
We get rid of parentheses
-1/6(x-2)+1/3(x+3)-x+7=0
We calculate fractions
-x+(-3xx/(6(x-2)*3(x+3))+(6xx/(6(x-2)*3(x+3))+7=0
We can not solve this equation

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