-1/6(x-2)+1/3(x+3)=x-7

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Solution for -1/6(x-2)+1/3(x+3)=x-7 equation: 



-1/6(x-2)+1/3(x+3)=x-7

We move all terms to the left:

-1/6(x-2)+1/3(x+3)-(x-7)=0



Domain of the equation: 6(x-2)!=0

x∈R





Domain of the equation: 3(x+3)!=0

x∈R



We get rid of parentheses

-1/6(x-2)+1/3(x+3)-x+7=0

We calculate fractions


-x+(-3xx/(6(x-2)*3(x+3))+(6xx/(6(x-2)*3(x+3))+7=0

We can not solve this equation

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