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-1/6x-5=2/3x
We move all terms to the left:
-1/6x-5-(2/3x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/6x-(+2/3x)-5=0
We get rid of parentheses
-1/6x-2/3x-5=0
We calculate fractions
(-3x)/18x^2+(-12x)/18x^2-5=0
We multiply all the terms by the denominator
(-3x)+(-12x)-5*18x^2=0
Wy multiply elements
-90x^2+(-3x)+(-12x)=0
We get rid of parentheses
-90x^2-3x-12x=0
We add all the numbers together, and all the variables
-90x^2-15x=0
a = -90; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-90)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-90}=\frac{0}{-180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-90}=\frac{30}{-180} =-1/6 $
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