-1/6x-x-3=-39

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Solution for -1/6x-x-3=-39 equation:



-1/6x-x-3=-39
We move all terms to the left:
-1/6x-x-3-(-39)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We add all the numbers together, and all the variables
-1x-1/6x+36=0
We multiply all the terms by the denominator
-1x*6x+36*6x-1=0
Wy multiply elements
-6x^2+216x-1=0
a = -6; b = 216; c = -1;
Δ = b2-4ac
Δ = 2162-4·(-6)·(-1)
Δ = 46632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{46632}=\sqrt{4*11658}=\sqrt{4}*\sqrt{11658}=2\sqrt{11658}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216)-2\sqrt{11658}}{2*-6}=\frac{-216-2\sqrt{11658}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216)+2\sqrt{11658}}{2*-6}=\frac{-216+2\sqrt{11658}}{-12} $

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