-1/8(z+3)=1/2(z-6)

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Solution for -1/8(z+3)=1/2(z-6) equation: 



-1/8(z+3)=1/2(z-6)

We move all terms to the left:

-1/8(z+3)-(1/2(z-6))=0



Domain of the equation: 8(z+3)!=0

z∈R





Domain of the equation: 2(z-6))!=0

z∈R



We calculate fractions


(-2zz/(8(z+3)*2(z-6)))+(-8zz/(8(z+3)*2(z-6)))=0



We calculate terms in parentheses: +(-2zz/(8(z+3)*2(z-6))), so:

-2zz/(8(z+3)*2(z-6))

We multiply all the terms by the denominator


-2zz

Back to the equation:

+(-2zz)





We calculate terms in parentheses: +(-8zz/(8(z+3)*2(z-6))), so:

-8zz/(8(z+3)*2(z-6))

We multiply all the terms by the denominator


-8zz

Back to the equation:

+(-8zz)



We get rid of parentheses

-2zz-8zz=0

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