-1/9(n+5)=-1/5(n+3)

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Solution for -1/9(n+5)=-1/5(n+3) equation: 



-1/9(n+5)=-1/5(n+3)

We move all terms to the left:

-1/9(n+5)-(-1/5(n+3))=0



Domain of the equation: 9(n+5)!=0

n∈R





Domain of the equation: 5(n+3))!=0

n∈R



We calculate fractions


(-5nn/(9(n+5)*5(n+3)))+(-(-9nn)/(9(n+5)*5(n+3)))=0



We calculate terms in parentheses: +(-5nn/(9(n+5)*5(n+3))), so:

-5nn/(9(n+5)*5(n+3))

We multiply all the terms by the denominator


-5nn

Back to the equation:

+(-5nn)





We calculate terms in parentheses: +(-(-9nn)/(9(n+5)*5(n+3))), so:

-(-9nn)/(9(n+5)*5(n+3))

We multiply all the terms by the denominator


-(-9nn)

We get rid of parentheses

9nn

Back to the equation:

+(9nn)



We get rid of parentheses

-5nn+9nn=0

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