-1/9(x-27)+1-3(x+3)=x+25

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Solution for -1/9(x-27)+1-3(x+3)=x+25 equation: 



-1/9(x-27)+1-3(x+3)=x+25

We move all terms to the left:

-1/9(x-27)+1-3(x+3)-(x+25)=0



Domain of the equation: 9(x-27)!=0

x∈R



We multiply parentheses

-1/9(x-27)-3x-(x+25)-9+1=0

We get rid of parentheses

-1/9(x-27)-3x-x-25-9+1=0

We multiply all the terms by the denominator


-3x*9(x-27)-x*9(x-27)-25*9(x-27)-9*9(x-27)+1*9(x-27)-1=0

Wy multiply elements

-27x^2(x-9x^2(x-225x(x-81x(x+9x(x-1=0

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