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-1/9(x-27)+1/3(x+3=x+25
We move all terms to the left:
-1/9(x-27)+1/3(x+3-(x+25)=0
Domain of the equation: 9(x-27)!=0
x∈R
Domain of the equation: 3(x+3-(x+25)!=0We calculate fractions
x∈R
(-3xx/(9(x-27)*3(x+3-(x+25))+(9xx/(9(x-27)*3(x+3-(x+25))=0
We calculate terms in parentheses: +(-3xx/(9(x-27)*3(x+3-(x+25))+(9xx/(9(x-27)*3(x+3-(x+25)), so:
-3xx/(9(x-27)*3(x+3-(x+25))+(9xx/(9(x-27)*3(x+3-(x+25)
We can not solve this equation
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