-1/9(x-27)+1/3(x+3=x+67

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Solution for -1/9(x-27)+1/3(x+3=x+67 equation: 



-1/9(x-27)+1/3(x+3=x+67

We move all terms to the left:

-1/9(x-27)+1/3(x+3-(x+67)=0



Domain of the equation: 9(x-27)!=0

x∈R





Domain of the equation: 3(x+3-(x+67)!=0

x∈R



We calculate fractions


(-3xx/(9(x-27)*3(x+3-(x+67))+(9xx/(9(x-27)*3(x+3-(x+67))=0



We calculate terms in parentheses: +(-3xx/(9(x-27)*3(x+3-(x+67))+(9xx/(9(x-27)*3(x+3-(x+67)), so:

-3xx/(9(x-27)*3(x+3-(x+67))+(9xx/(9(x-27)*3(x+3-(x+67)

We can not solve this equation

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