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-1/9x+5/9=1/5x-1
We move all terms to the left:
-1/9x+5/9-(1/5x-1)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 5x-1)!=0We get rid of parentheses
x∈R
-1/9x-1/5x+1+5/9=0
We calculate fractions
(-5x)/3645x^2+(-729x)/3645x^2+25x/3645x^2+1=0
We multiply all the terms by the denominator
(-5x)+(-729x)+25x+1*3645x^2=0
We add all the numbers together, and all the variables
25x+(-5x)+(-729x)+1*3645x^2=0
Wy multiply elements
3645x^2+25x+(-5x)+(-729x)=0
We get rid of parentheses
3645x^2+25x-5x-729x=0
We add all the numbers together, and all the variables
3645x^2-709x=0
a = 3645; b = -709; c = 0;
Δ = b2-4ac
Δ = -7092-4·3645·0
Δ = 502681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{502681}=709$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-709)-709}{2*3645}=\frac{0}{7290} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-709)+709}{2*3645}=\frac{1418}{7290} =709/3645 $
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