-1/ln(x)=0.01

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Solution for -1/ln(x)=0.01 equation: 


D( x )

x <= 0

ln(x) = 0

x <= 0

ln(x) = 0

ln(x) = 0

ln(x) = ln(e^0)

x = e^0

x = 1

x in (0:1) U (1:+oo)

-1/ln(x) = 0.01 // - 0.01

-1/ln(x)-0.01 = 0

t_1 = ln(x)

-1/t_1-0.01 = 0

-1*t_1^-1 = 0.01 // : -1

t_1^-1 = -0.01

-1 < 0

1/(t_1^1) = -0.01 // * t_1^1

1 = -0.01*t_1^1 // : -0.01

-100 = t_1^1

t_1 = -100

ln(x) = -100

ln(x) = ln(e^-100)

x = e^-100

x = 0

x in { 0} 

x belongs to the empty set

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