-10(-7+3k)=1/5(100+50k)

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Solution for -10(-7+3k)=1/5(100+50k) equation: 



-10(-7+3k)=1/5(100+50k)

We move all terms to the left:

-10(-7+3k)-(1/5(100+50k))=0



Domain of the equation: 5(100+50k))!=0

k∈R



We add all the numbers together, and all the variables

-10(3k-7)-(1/5(50k+100))=0

We multiply parentheses

-30k-(1/5(50k+100))+70=0

We multiply all the terms by the denominator


-30k*5(50k+100))-(1+70*5(50k+100))=0

Wy multiply elements

-150k^2(5+350k(5=0

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