-10(1+4b)+10=6(-7-8)+6

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Solution for -10(1+4b)+10=6(-7-8)+6 equation: 



-10(1+4b)+10=6(-7-8)+6

We move all terms to the left:

-10(1+4b)+10-(6(-7-8)+6)=0

We add all the numbers together, and all the variables

-10(4b+1)+10-(6(-15)+6)=0

We add all the numbers together, and all the variables

-10(4b+1)+94=0

We multiply parentheses

-40b-10+94=0

We add all the numbers together, and all the variables

-40b+84=0

We move all terms containing b to the left, all other terms to the right

-40b=-84

b=-84/-40

b=2+1/10

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