-10(1+4b)+12=-1b-8)+6

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Solution for -10(1+4b)+12=-1b-8)+6 equation: 



-10(1+4b)+12=-1b-8)+6

We move all terms to the left:

-10(1+4b)+12-(-1b-8)+6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(-1b-8)+12+6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(-1b-8)=0

We multiply parentheses

-40b-(-1b-8)-10=0

We get rid of parentheses

-40b+1b+8-10=0

We add all the numbers together, and all the variables

-39b-2=0

We move all terms containing b to the left, all other terms to the right

-39b=2

b=2/-39

b=-2/39

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