-10(1+4b)+12=6(-7b-8)-6

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Solution for -10(1+4b)+12=6(-7b-8)-6 equation: 



-10(1+4b)+12=6(-7b-8)-6

We move all terms to the left:

-10(1+4b)+12-(6(-7b-8)-6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(6(-7b-8)-6)+12=0

We multiply parentheses

-40b-(6(-7b-8)-6)-10+12=0



We calculate terms in parentheses: -(6(-7b-8)-6), so:

6(-7b-8)-6

We multiply parentheses

-42b-48-6

We add all the numbers together, and all the variables

-42b-54

Back to the equation:

-(-42b-54)



We add all the numbers together, and all the variables

-40b-(-42b-54)+2=0

We get rid of parentheses

-40b+42b+54+2=0

We add all the numbers together, and all the variables

2b+56=0

We move all terms containing b to the left, all other terms to the right

2b=-56

b=-56/2

b=-28

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