-10(1+4b)=12+6(-7b-8)-6

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Solution for -10(1+4b)=12+6(-7b-8)-6 equation: 



-10(1+4b)=12+6(-7b-8)-6

We move all terms to the left:

-10(1+4b)-(12+6(-7b-8)-6)=0

We add all the numbers together, and all the variables

-10(4b+1)-(12+6(-7b-8)-6)=0

We multiply parentheses

-40b-(12+6(-7b-8)-6)-10=0



We calculate terms in parentheses: -(12+6(-7b-8)-6), so:

12+6(-7b-8)-6

determiningTheFunctionDomain
6(-7b-8)+12-6

We add all the numbers together, and all the variables

6(-7b-8)+6

We multiply parentheses

-42b-48+6

We add all the numbers together, and all the variables

-42b-42

Back to the equation:

-(-42b-42)



We get rid of parentheses

-40b+42b+42-10=0

We add all the numbers together, and all the variables

2b+32=0

We move all terms containing b to the left, all other terms to the right

2b=-32

b=-32/2

b=-16

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