-10(1+4b)=12=6(-7b-8)+6

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Solution for -10(1+4b)=12=6(-7b-8)+6 equation: 



-10(1+4b)=12=6(-7b-8)+6

We move all terms to the left:

-10(1+4b)-(12)=0

We add all the numbers together, and all the variables

-10(4b+1)-12=0

We multiply parentheses

-40b-10-12=0

We add all the numbers together, and all the variables

-40b-22=0

We move all terms containing b to the left, all other terms to the right

-40b=22

b=22/-40

b=-11/20

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