-10(1+4h)+12=6(-7h-8)+6

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Solution for -10(1+4h)+12=6(-7h-8)+6 equation: 



-10(1+4h)+12=6(-7h-8)+6

We move all terms to the left:

-10(1+4h)+12-(6(-7h-8)+6)=0

We add all the numbers together, and all the variables

-10(4h+1)-(6(-7h-8)+6)+12=0

We multiply parentheses

-40h-(6(-7h-8)+6)-10+12=0



We calculate terms in parentheses: -(6(-7h-8)+6), so:

6(-7h-8)+6

We multiply parentheses

-42h-48+6

We add all the numbers together, and all the variables

-42h-42

Back to the equation:

-(-42h-42)



We add all the numbers together, and all the variables

-40h-(-42h-42)+2=0

We get rid of parentheses

-40h+42h+42+2=0

We add all the numbers together, and all the variables

2h+44=0

We move all terms containing h to the left, all other terms to the right

2h=-44

h=-44/2

h=-22

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