-10(1-4b)+12=6(-7b-8)+6

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Solution for -10(1-4b)+12=6(-7b-8)+6 equation: 



-10(1-4b)+12=6(-7b-8)+6

We move all terms to the left:

-10(1-4b)+12-(6(-7b-8)+6)=0

We add all the numbers together, and all the variables

-10(-4b+1)-(6(-7b-8)+6)+12=0

We multiply parentheses

40b-(6(-7b-8)+6)-10+12=0



We calculate terms in parentheses: -(6(-7b-8)+6), so:

6(-7b-8)+6

We multiply parentheses

-42b-48+6

We add all the numbers together, and all the variables

-42b-42

Back to the equation:

-(-42b-42)



We add all the numbers together, and all the variables

40b-(-42b-42)+2=0

We get rid of parentheses

40b+42b+42+2=0

We add all the numbers together, and all the variables

82b+44=0

We move all terms containing b to the left, all other terms to the right

82b=-44

b=-44/82

b=-22/41

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